Question

Решить систему уравнений

x+4=z
y+3=z
6x-5y=2

Answer 1

х + 4 = z                                                                              x + 4 = y + 3
y + 3 = z    => (Подставим значение z в первое уравнение) y + 3 =z          =>
6x - 5y = 2                                                                          6x - 5y = 2 

x = y - 1             x = y - 1          x = y - 1            x = 7
y + 3 = z      =>  y + 3 = z    => z = y + 3      => z = 11 
6x - 5y = 2          6y - 5y = 8       y= 8                 y = 8

Answer 2

$x+y=z\y+3=z\6x-5y=2\x=3\y=cfrac{16}{5}\z=cfrac{31}{5}$