Question

пожалуйста решите уравнение :

1) x+3/20=5/12+2/9

2) 5/7-y=1/54+1/9+10/27

3) (4/5-k)-1/3=1/6-1/10

Answer 1

$x+cfrac{3}{20}=cfrac{5}{12}+cfrac{2}{9}\x+cfrac{3}{20}=cfrac{23}{36}\x=cfrac{22}{45}$
$cfrac{5}{7}-y=cfrac{1}{54}+cfrac{1}{9}+cfrac{10}{27}\cfrac{5}{7}-y=cfrac{1}{2}\y=cfrac{3}{14}$
$left(cfrac{4}{5}-kright) - cfrac{1}{3}=cfrac{1}{6}-cfrac{1}{10}\cfrac{4}{5}-k=cfrac{2}{5}\k=cfrac{2}{5}$