Question

Разложите на множители.
1)2x^3-3x^2+3x-1
2)x^2+2x-y^2-6y-8

Answer 1

2x^3-3x^2+3x-1=x^3+(x-1)^3=(2x-1)(x^2-x(x-1)+(x-1)^2)=(2x-1)(x^2-x+1)

x^2+2x-y^2-6y-8=(x+1)^2-(y+3)^2=(x+y+4)(x-y-2)