Question

Найдите корень уравнения √1-x=x+1 помогите плз

Answer 1

$sqrt{1-x}=x+1 \ \ left { {{1-x=(x+1)^2} atop {1-x geq 0,x+1 geq 0}} right. \ \ left { {{1-x=x^2+2x+1} atop {x leq 1,x geq -1}} right. \ \ left { {{x^2+3x=0} atop {x E[-1; 1]}} right. \ \ left { {{x*(x+3)=0} atop {x E[-1; 1]}} right. \ \ left { {{x=0, x=-3} atop {x E[-1; 1]}} right. \ x=0$