Question

Решите неравенство:
0,1^2х+5>100

Answer 1

$0.1^{2x+5} geq 100$
$0.1^{2x+5} geq 0.1^{-2}$
$0<0.1<1; 2x+5 leq -2$
$2x+5 leq -2$
$2x leq -2-5$
$2x leq -7$
$x leq -7:2$
$x leq -3.5$
x є $(-infty; -3.5]$