Question

решить ур-ие lg(3x-8)+lg x=lg(2х-3)

Answer 1

$lg(3x-8)+lg x=lg(2x-3)\ begin{cases} x(3x-8)=2x-3\ x>0\ 2x-3>0 end{cases}\ begin{cases} 3x^2-10x+3=0\ x>frac32 end{cases}\ begin{cases} left[begin{array}{l} x=3\ x=frac13 end{array}right.\ x>frac32 end{cases}\ boxed{x=3}$