Question

решите систему уравнений

 

left { {{x-2y=0} atop {y^2-3x=0}} right.

Answer 1

X - 2Y = 0 --> X = 2Y

Y^2 - 3X = 0

Y^2 - 6Y = 0

Y*(Y-6) = 0

Y1 = 0 ---> X1 = 0

Y2 = 6 ---> X2 = 12