Question

Найти интеграл 

∫(((x^(-1/3))-1)/(sqrt[3]{x^{2}}))dx

Answer 1

$int frac{x^{-frac{1}{3}}-1}{sqrt[3]{x^2}} dx=\\ int (x^{-frac{1}{3}}-1)x^{-frac{2}{3}} dx=\\ int (x^{-1}-x^{-frac{2}{3}}) dx=\\ ln|x|-frac{x^{-frac{2}{3}+1}}{-frac{2}{3}+1}+C=\\ ln|x|-3sqrt[3] {x}+C$

 

C є R