Question

Решите неравенство:
-14:(x-5)2-2>=0

Answer 1

$frac{-14}{(x-5)^2-2} geq 0 \ (x-5)^2-2 textless 0 \ x^2+25-10x-2 textless 0 \ x^2+23-10x textless 0 \ D=b^2-4ac=529-4*1*(-10)=569 \ x_1= frac{-b+ sqrt{D} }{2a} =frac{-23+ sqrt{569} }{2} \ x_1= frac{-b- sqrt{D} }{2a} =frac{-23- sqrt{569} }{2} \ Otvet:x = [frac{-23- sqrt{569} }{2};frac{-23+ sqrt{569} }{2}]$