Question

2 arcsin (-корень 3/2) + arcctg (-1) + arccos корень 2/2

Answer 1

$2arcsin (-frac{sqrt{3}}{2}) + arcctg (-1) + arccos (frac{sqrt{2}}{2}) =\ 2 (-frac{pi}{3}) - ( frac{pi}{4}) + ( frac{pi}{4}) = -frac{2pi}{3}$