Question

(2,5у -4)(6у+1,8) = 0 Помогите Плиз((((

Answer 1

(2,5y-4)(6y+1,8)=0

(a.b=0 ⇔ a=0 ∨ b=0)

1)2,5y-4=0, 2,5y=4, y=4/2,5=16/10=1,6, y=1,6
2)6y+1,8=0, 6y=-1,8, y=-1,8/6, y=-0,3