Question

log0.3(2x-4)>log0.3(x+1)

Answer 1

$<var>log_{0.3}(2x-4)>log{0.3}(x+1)\2x-4>0 ||x+1>0\x>2||x>-1\\a=0,3 (<1)\2x-4<x+1\x<5\\boxed{xin(2;5)}< var=$