Question

Найти производную y=3x^7-6x^5-4x^2+17
y=(x^3-2)(x^2+1)

Answer 1

Держи.

$y=3x^7-6x^5-4x^2+17\y'=21x^6-30x^4-8x\\y=(x^3-2)(x^2+1)\y'=(x^3-2)'(x^2+1)+(x^3-2)(x^2+1)'=3x^2(x^2+1)+2x(x^3-2)=\=3x^4+3x^2+2x^4-4x=5x^4+3x^2-4x$