Question

Помогите решить уравнение срочно.(кроме 1,2,3,4,5)

Answer 1

$6.;;11x +103 = 1 +(12x-31)\\11x - 12x = 1-31-103\\x = 133\ \ \7.;;(2x+3) - (5x+11) = 7 + (13-2x)\ \2x - 5x + 2x = 7+13 - 3 + 11\\x = -28\\ \8.;;(2x+3)+(3x+4) + (5x+5) = 12 -7x\\2x+3x+5x+7x = 12 - 3 - 4 - 5\\17x = 0\\x = 0$

9.

$6x = 1 - (4-6x)$

$6x - 6x = 1-4$

$0x = -3$ - нет решений

10.

$6y - (y-4) = 4+5y$

$6y - y - 5y = 4 - 4$

$0y = 0$  y - любое число

$11.;;5.6 - 7y = -4(2y-0.9) + 2.4\\-7y + 8y = 3.6 + 2.4 - 5.6\\y = 0.4\\ \12.;;x-0.5 = 2(0.3x - 0.2)\\x - 0.6x = -0.4 + 0.5\\0.4x = 0.1\\x = frac{0.1}{0.4} = frac{1}{4} = 0.25$

$13.;;3(2.5 - 2x) = 13.5 - 14x\\-6x + 14x = 13.5 - 7.5\\8x = 6\\x = frac{6}{8} = frac{3}{4} = 0.75\\ \14.;; 0.6y - 1.5 = 0.3(y-4)\\0.6y-0.3y = -1.2 + 1.5\\0.3y = 0.3\\y = 1\\ \15.;; 0.5(4-2a) = a - 1.8\\-a - a = -1.8 - 2\\-2a = -3.8\\a = 1.9$

$16.;; 7(3+x) = 2(x-5) +8\\7x - 2x = -10 + 8 -21\\5x = -23\\x = -frac{23}{5} = -4frac{3}{5} = -4.6$

$17.;;-0.2(5-0.7x) + 0.02 = 1.4(x-1.6)$

$0.14x - 1.4x = -2.24 + 1 - 0.02$

$-1.26x = -1.26$

$x= 1$

$18. ;; 1.2(3b+5) = 2(2.4b - 3.6)\\3.6b - 4.8b = -7.2 - 6\\-1.2b = -13.2\\b = frac{13.2}{1.2} = frac{132}{12} = 11\\ \19. ;;3.2(5x-1) = 3.6x - 9.4\\16x - 3.6x = -9.4+3.2\\12.4x = -6.2\\x = -0.5\\ \20.;;8(0.7x -4) - 2(0.2x - 3) = -39\\5.6x -0.4x = -39+32-6\\5.2x = -13\\x = -frac{13}{5.2} = -frac{130}{52} = -frac{5}{2} = -2.5\\ \21.;;-3(2.1z - 4) - 4.2 = 1.2(-5z + 0.5)\\-6.3z+6z = 0.6 - 12 + 4.2\\-0.3z = -7.2\\z = 24$

$22.;; 6.4(2-3y) = 6(0.8y-1) +6.8\\-19.2y -4.8y = -6+6.8-12.8\\-24y = -12\\y = 0.5$