Question

cos(n/2-n/3)
tg(n/4+n/6)
помогите пожалуйста

Answer 1

$cos( frac{pi }{2}- frac{pi }{3})=sin frac{pi }{3}=frac{sqrt3}{2}\\\tg( frac{pi}{4}+frac{pi }{6} )=frac{ tgfrac{pi}{4}+tgfrac{pi}{6}}{1-tgfrac{pi}{4}cdot tgfrac{pi}{6}}= frac{frac{sqrt2}{2}+frac{sqrt3}{3}}{1- frac{sqrt2}{2}cdot frac{sqrt3}{3} } = frac{(3sqrt2+2sqrt3)cdot 6}{6cdot (6-sqrt2cdot sqrt3)} =\\= frac{sqrt6(sqrt3+sqrt2)}{sqrt6(sqrt6-1)} = frac{sqrt3+sqrt2}{sqrt6-1}$