Question

помогите пж номер1в,номер2,номер3

Answer 1

1. в) (m+3/4n)(m–3/4n)=m^2–9/16n^2

2. a) (m–2)^2–(m+1)(m–3)=m^2–4m+
4–m^2+3m–m+3=7–2m
б) 5(а–с)^2+10ас=5а^2–10ас+5с^2+
+10ас=5(а^2+с^2)
в) р^3+(2–р)(р^2+2р+4)=р^3+8–р^3=
=8

3. (20а^4–4а^3b):4a=4a^3(5a–b):4a=
=a^2(5a–b)=9(15+4)=171