Question

√2*cos^2-cosx=sin(x-pi/2)

Answer 1

а)√2cos^2(x)=sin(x-п/2)

√2cos^2(x)+cosx=0

cosx(√2cosx+1)=0

cosx=0 или cosx=-1/√2

 x=п/2+пk, x=+-3п/4+2пk;

б) -3п/2;-3п/4.

Ответ: а)x=п/2+пk, x=+-3п/4+2пk;

б)-3п/2;-3п/4.