Question

Помогите пожалуйста с 3 номером!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

1/(3*(x-4))+1/(2*(x²+3))+1/(x³-4x²+3x-12)=0
1/(3*x-4))+1/(2*(x²+3))+1/(x²(x-4)+3(x-4))=0
1/(3*(x-4))+1/(2*(x²+3))+1/((x-4)*(x²+3))=0
2*(x²+3)+3*(x-4)+3*2=0
2x²+6+3x-12+6=0
2x²+3x=0
x(2x+3)=0
x₁=0   x₂=-1,5.