Question

|2+3х|<4,7; -8《х+3《8 запишите в виде двойного неравенства

Answer 1

|2+3х|<4,7
-4,7<2+3х<4,7
-4,7-2<2+3х-2<4,7-2
-6,7<3x<2,7
$- frac{67}{10} :3 textless x textless frac{27}{10} :3$
$- frac{67}{10} * frac{1}{3} textless x textless frac{27}{10} : frac{1}{3}$
$- frac{67}{30} textless x textless frac{27}{30} :$


|2+3х|≤8
-8≤2+3х≤8
-10≤3x≤6
$- frac{10}{3} leq x leq 2$
$-3frac{1}{3} leq x leq 2$


|2+3х|≤х+3
$left { {2+3x leq x+3} atop {2x+3 geq -(x+3)}} right.$
$left { {3x-x leq 3-2} atop {2x+3 geq -x-3}} right.$
$left { {2x leq 1} atop {2x+x geq -3-3}} right.$
$left { {x leq 1/2} atop {x geq -2}} right.$
x∈[-2;1/2]