Question

lim...
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Answer 1

Решение задания!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$lim_{_{x to 2}} frac{sqrt{4+x}-2}{x}= frac{sqrt{6}-2}{2}=frac{sqrt{6}}{2}-1=sqrt{frac{6}{4}}-1=sqrtfrac{3}{2}-1 \lim_{_{xto 1}}frac{x^2-1}{x-1}=lim_{_{xto 1}}frac{(x-1)(x+1)}{x-1}=lim_{_{xto 1}}(x+1)=2$