Question

z1=i^3+4i^4 z2=i^2-3(-i)^3

Answer 1

Так как i^2 = - 1, то

z1 = i^2* i + 4*(i^2)^2 = - i + 4*(-1)^2 = 4 - i 

z2 = i^2 - 3(-i)^3 = i^2 + 3i^3 = i^2 + 3i^2*i = - 1 - 3i