Question

Запишите числа в виде квадрата разности:60, 44 ,72, 120, 58
Очень надо даю 30 баллов

Answer 1

$60= (sqrt{60} )^{2} =(2 sqrt{15} )^{2} =(3 sqrt{15}- sqrt{15} )^{2} =( sqrt{135}- sqrt{15})^{2}$
$44=( sqrt{44} )^{2} =(2 sqrt{11} )^{2} =(3 sqrt{11}- sqrt{11})^{2} =( sqrt{99}- sqrt{11} )^{2}$
$72= (sqrt{72} )^{2} =(6 sqrt{2})^{2} =(7 sqrt{2} - sqrt{2} )^{2} =( sqrt{98} - sqrt{2} )^{2}$
$120=( sqrt{120} )^{2} =(2 sqrt{30} )^{2} =(3 sqrt{30} - sqrt{30})^{2} =( sqrt{270} - sqrt{30}) ^{2}$
$58=( sqrt{58} )^{2} =( sqrt{ frac{116}{2} } )^{2} =(2 sqrt{ frac{29}{2} } )^{2} =(4sqrt{ frac{29}{2} }-2sqrt{ frac{29}{2} })^{2} = \ =( sqrt{232} - sqrt{58})^{2}$