Question

Tg(a)+Ctg(a)=3

Tg(a)-Ctg(a)

Answer 1

(tgα+ctgα)²=3²
tg²α+ctg²α+2tgα ctgα=9
tg²α+ctg²α+2=9
tg²α+ctg²α=7
(tgα-ctgα)²=tg²α+ctg²α-2tgα ctgα=tg²α+ctg²α-2
⇒tg²α+ctg²α-2=7-2=5
Ответ: 5