Question

40 балов. Система уравнений
х-4у=2
ху+2у=8

Answer 1

$left { {{x-4y=2} atop {xy+2y=8}} right. \ \ left { {{x=4y+2} atop {(4y+2)y+2y=8}} right. \ \ (4y+2)y+2y=8 \ 4y^2+2y+2y=8 \ 4y^2+4y-8=0 |:4 \ y^2+y-2=0 \ \ y_1=-2 \ y_2=1 \ \ x=4y+2 \ \ x_1=4y_1+2=4*(-2)+2=-6 \x_2=4y_2+2=4*1+2=6 \ \ OTBET: (-6;-2); (6;1)$