Question

помогите с пределами пж

Answer 1

1)=[0/0]=lim x→5 (x-5)(x+5) / x-5=lim x→5 x+5=10
2)=-9-5/9-3+1=-14/7=-2
3)=[0/0]=limx→5 (x-5)(√x-1 +2) / (x-1)-4=limx→5 (x-5)(√x-1 +2) / x-5 =limx→5 √x-1 +2=4
4)=limx→∞ 3+1/x²+4/x³ / -1-1/x+14/x³ = -3