Question

2-log7(6x-5)=0 решить уравнение

Answer 1

$[begin{gathered} 2 - {log _7}left( {6x - 5} right) = 0 hfill \ left{ begin{gathered} {log _7}left( {6x - 5} right) = 2, hfill \ 6x - 5 > 0; hfill \ end{gathered} right. hfill \ left{ begin{gathered} 6x - 5 = 49, hfill \ x > frac{5}{6}; hfill \ end{gathered} right. hfill \ left{ begin{gathered} x = 9, hfill \ x > frac{5}{6}; hfill \ end{gathered} right. hfill \ end{gathered} ]$

 

ответ:9