Question

Найдите корень уравнения:
5y+7(3-y)=3(5-2y)-6
7y-4(3y+5)=2-3(4y-9)

Answer 1

5y+7(3-y)=3(5-2y)-6
5y+21-7y=15-6y-6
5y-7y+6y=-21-6+15
4y=-12
y=(-12):4
y=-3

7y-4(3y+5)=2-3(4y-9)
7y-12y-20=2-12y+27
7y-12y+12y=20+2+27
7y=49
y=49:7
y=7

Answer 2

да

Answer 3

5у+21-7у = 15-6у-6
5у+6у-7у = 15-6-21
4у = -12
у - -3

7у-12у-20 = 2-12у+27
7у-12у+12у = 2+27+20
7у = 49
у = 7