Question

(4-x)^2+(3-x)^2=2x^2-3

Answer 1

(4-x)^2+(3-x)^2=2x^2-3
16 - 8х + х^2 + 9 - 6х + х^2 = 2х^ - 3
х^2 + х^2 - 2х^2 - 8х - 6х = -3 - 16 - 9
-14х = -28
х = -28 : (-14)
х = 2