Question

Реши уравнение: 24t2−(6t−4)⋅(4t+1)=−2

Answer 1

24t2-(24t²-6t-16t-4)+2=0
24t2-24t²+6t+16t+4+2=0
48t-24t²+22t+6=0
70t-24t²+6=0
-24t²+70t+6=0
D=√ (-70)²-4×(-24)×6=√4900+576=√5476=74
x1= -70+74/2×(-24)=4/48=1/12
x2= -70 - 74/2×(-24)=-144/-48=3
Ответ: 1/12,3