Question

решение неравенств,log

Answer 1

ОДЗ:2х+7>0
2х> -7 Х> -3,5
log1/2 (2x+7)^1/3 <= -
log1/2 1/2
log1/2 (2x+7)^1/3 <=log1/2(1/2)^-1
(2x+7)^1/3 <= 2
2x+7<=8
2x <= 1
X<=1/2
///////////////////////
-----(-3,5)--------(1/2)-----
\\\\\\\\\\\
Ответ: (-3,5 ; 1/2]


ОДЗ Х>0
lg9^1/2-lgx>lg3
lg 3/x>lg3
3/Х>3
3х<3
Х<1
Х€(0;1)