Question

1) 2x^2+5x=-2
2) 3х^2+8x=4

Answer 1

$displaystyle textbf{1)}\\2x^2+5x=-2\\2x^2+5x+2=0\\x_{1,2}= frac{-5pm sqrt{25-16} }{4}= frac{-5pm 3}{4}=(-2),left(- frac{1}{2} right) \\textbf{2)}\\3x^2+8x=4\\3x^2+8x-4=0\\x_{1,2}= frac{-8pm sqrt{64+48} }{6}= frac{-8pm sqrt{112 } }{6}= frac{-8pm 4 sqrt{7} }{6} = frac{-4pm 2 sqrt{7} }{3}$

Answer 2

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