Question

cos(π+2а)+sin(π+2а)*tg(π/2+а)=?
можете помочь мне срочно нужно

Answer 1

Cos(π+2α)+sin(π+2α)*tg(π/2+α)=-cos2α-sin2α*(-ctgα)=
=-(cos²α-sin²α)+2sinαcosα*cosα/sinα=-cos²α+sin²α+2cos²α=cos²α+sin²α=1.