Question

cos(2x+ п/6)=0 помогите,пожалуйста

Answer 1

п3-2x=+п3+2пn
-2x=-2п3-п3+2пn U-2x=п3-п3+2пn
-2x=-2п3+2пn U-2x=2пn
x=п3+пn U x=пn

Answer 2

Решение
Cos(2x+π/6)=0
2x + π/6 = π/2 + πk, k ∈ Z
2x = π/2 - π/6 + πk, k ∈ Z
2x = π/3 + πk, k ∈ Z
x = π/6 + πk/2, k ∈ Z