Question

решить уравнения:1)(икс+323)-561=2198;2) 1946-(1757-икс)=354;3)1380÷(37-икс÷26)=115

Answer 1

(х+323)-561=2198
х+323=2198+561
х+323=2759
х=2759-323
х=2436

1946-(1757-х)=354
1757-х=1946-354
1757-х=1592
х=1757-1592
х=165

1380:(37-х:26)=115
37-х:26=1380:115
37-х:26=12
х:26=37-12
х:26=25
х=25*26
х=650

Answer 2

1) (X+323)-561=2198 X+323=2759 X=2436 2) 1946-(1757-x)=354 1946-354=1757-X 1592=1757-x X=1757-1592 X=165 3) 1380:(37-х:26)=115 37-х:26=1380:115 37-х:26=12 х:26=37-12 х:26=25 х=650