Question

(x+1)(x-1)(x-2)-(x^2+7x)(x-4)-2=2x

Answer 1

(x+1)(x-1)(x-2) - (x^2+7x)(x-4) - 2 = 2x

(x^2-1)(x-2) - (x^2+7x)(x-4) - 2x - 2 = 0

x^3 - x - 2x^2 + 2 - x^3 - 7x^2 + 4x^2 + 28x - 2x - 2 = 0

(x^3 - x^3) + (-2x^2 - 7x^2 + 4x^2) + (28x - x - 2x) + (2 - 2) = 0

-5x^2 + 25x = 0

5x(-x + 5) = 0

x1 = 0; x2 = 5