Question

Продифференцировать функцию:

Answer 1

$(4sin^2(x+y))'=x' \ 8sin(x+y)*(sin(x+y))'=1 \ 8sin(x+y)cos(x+y)*(x+y)'=1 \ 4sin(2(x+y))*(1+y')=1 \ y'+1= frac{1}{4sin(2(x+y))} \ y'= frac{1}{4sin(2(x+y))} -1$