Question

Вычислите предел lim x → 0 sin17x/sin5x

Answer 1

$lim_{x->0} frac{sin (17x)}{sin (5x)}=$
$lim{x->0} frac{sin(17x)}{17x}*frac{5x}{sin(5x)}*frac{17x}{5x}=$
$1*1*frac{17}{5}=frac{17}{5}$