Question

3cosa-4sina/4sina+cosa, если tga=1

Answer 1

$tga=1\\ frac{3cosa-4sina}{4sina+cosa} =frac{cosacdot (3-4tga)}{cosacdot (4tga+1))}=frac{3-4tga}{4tga+1}=frac{3-4}{4+1}=frac{-1}{5}$