Question

3ctg(2x-п/2)=корень3

Answer 1

3ctg(2x-pi/2)=v3
-3ctg(pi/2-2x)=v3
-3tg2x=v3
tg2x=-v3/3
2x=-pi/6 + pi*k
x=-pi/12 + 1/2pi*k

Answer 2

3ctg(x-π/2)=√3
ctg(x-π/2)=√3/3
-ctg(π/2-2x)=√3/3
tg2x=-√3/3
2x=-π/6+πn
x=-π/12+πn/2,n∈z