Question

(-1/3*а^3*в)^3*(-2 целых 1/4*а^3*в)

Answer 1

$displaystyle (- frac{1}{3}a^{3}b)^{3} *(-2 frac{1}{4}*a^{3}b)= frac{1}{27}a^{9}b^{3}* frac{9}{4}a^{3}b= frac{1}{12}a^{12}b^{4};$