Question

Упростить sin6x/cos3x

Answer 1

sin6x/cos3x=(2sin3x*cos3x)/cos3x=2sin3x

Answer 2

Если $cos(3x) neq 0$
$3x neq frac{pi}{2}+pi n,nin Z$
$x neq frac{pi}{6}+ frac{pi n}{3} ,nin Z$, то
$frac{sin(6x)}{cos(3x)}= frac{2*sin(3x)*cos(3x)}{1*cos(3x)}= frac{2*sin(3x)}{1}=2sin(3x)$