Question

интеграл от 0 до 2 dx/(2-0.5x)^2 [/tex]

Answer 1

 

$intlimits_0^2 frac{1}{(2-0.5x)^2}, dx =\\ frac{2}{2-0.5x} |limits_0^2 =\\ frac{2}{1} - frac{2}{2} = 1$