Question

Помогите::::::::::^^**()(;:"'#@#/^&

Answer 1

$left { {{x^2-x-6 geq 0} atop {x^2-4x textless 0}} right. ; left { {{(x-3)(x+2) geq 0} atop {x(x-4) textless 0}} right. ; left { {{xin (-infty ,-2, ]cup[, 3,+infty )} atop {xin (0,4)}} right. ; ; to \\xin [, 3,4)\\(x-3)(x+2) geq 0qquad +++[, -2, ]---[, 3, ]+++\\x(x-4) textless 0qquad +++(0)---(4)+++$

////////[ -2] ..............[3] //////////////////////
...................(0) ///////////////(4)............

Answer 2

проверьте решение, ответ должен быть только [3;4)