Question

Решите уравнение пж
36x^2-(3x-27)^2=0

Answer 1

36х^2-(9х^2-2*27*3х+27^2)=0
36х^2-9х^2+6*27х-27^2=0
27х^2+6*27х-27^2=0 |(:27)
х^2+6х-27=0
D=6^2-4*1*(-27)=36+4*27=36+108=144
x1=(-6-12)/2= -9
x2=(-6+12)/2= 3