Предмет: Алгебра, автор: dawselkkatusiks

Найдите наименьшее значение функции y = log3(x2 - 6x + 10) + 2

Ответы

Автор ответа: Аноним

Так как логарифмическая функция возрастающая, то наименьшее значение функции будет в точке вершины параболы $tt y=x^2-6x+10$

$tt y=x^2-6x+10=(x-3)^2+1$ - вершина параболы: $tt (3;1)$ (ветви направлены вверх!!!!)

$tt y=log_3((x-3)^2+1)+2=log_31+2=2$ - Наименьшее значение

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