Question

Помогите решить уравнение:
log2x+log4x+log8x=11/6

Answer 1

log2 x+log2² x +log2³ x=11/6
log2 x+(1/2)log2 x+(1/3)lo2 x=11/6
(log2 x)(1+1/2+1/3)=11/6
(log2 x)(11/6)=11/6
log2 x=1
x=2