Предмет: Алгебра, автор: NataliIvannikova

Решите пожалуйста
Вычислить y',если у =3х^2-4х/х-1

Ответы

Автор ответа: Dugan1986

0

y'=6x-[(x-1)*(4x)'-(x-1)'*(4x)]/(x-1)^2
y'=6x-[(x-1)*4-(4x)]/(x-1)^2
y'=6x-[4x-4-4x]/(x-1)^2
y'=6x-4/(x-1)^2

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