Question

Интеграл 1к0 (x^3-6x^5)dx

Answer 1

$intlimits^1_0 {(x^3-6x^5)} , dx = frac{x^4}{4}- x^6/^1_0= \ \ = frac{1}{4}-1-( frac{0}{4}-0)= frac{1-4}{4}=- frac{3}{4}$