Question

$Log_{3}(x-8) + Log_{3}x=2$

Answer 1

{x-8>0⇒x>8
{x>0
x∈(8;∞)
log(3)(x²-8x)=2
x²-8x=9
x²-8x-9=0
x1+x2=8 U x1*x2=-9
x1=-1не удов усл
х2=9

Answer 2

ответ: x=9