Question

Помогите пож (3-2i)*(-4-i) и 9-8iделен на-i+1 +(3i-1)

Answer 1

(3-2i)(-4-i)=-12+8i-3i-2=-14+5i

(9-8i)/(-i+1)+(3i-1))=(9-8i)(1+i)/(1+i)(1-i)+(3i-1)=(9-8i+9i+8)/(1+1)+(3i-1)=
=(17+i)/2+(3i-1)=(17+i+6i-2)/2=(15+7i)/2